Foldover in 2^{K - p} Designs

Strategies for dealiasing effects in follow-up experiments.

Kris Sankaran true
11-25-2021

Readings 8.6, 8.7, Rmarkdown

  1. The main drawback of fractional designs is that we can end up with aliased effects. However, there are specific ways to follow-up initial experiments in a way that dealiases these effects.
  1. We’ll discuss two dealiasing strategies, full-foldover and single-factor foldover. They are both particularly relevant in resolution III designs, where main effects can be confounded with order-2 interactions.

Full Foldover

3.Imagine that we want to delias main effects for all factors under study. * Assume that there aren’t any interaction effects with order > 2 * Idea: For a second fractional factorial run, reverse the signs of all factors

Setup for the $2^{7 - 4}$ design with foldover used in the eye focus experiment. The second panel is the full foldover of the first.

Figure 1: Setup for the \(2^{7 - 4}\) design with foldover used in the eye focus experiment. The second panel is the full foldover of the first.

  1. What does this do? Let’s consider an the eye focus time example from the textbook (Example 8.7). The design is a \(2^{7 - 3}_{III}\) fractional factorial experiment (Seq == 1) that has then been folded over (Seq == 2) by reversing the signs of factors.

  2. Let’s consider the alias structure for the original fractional factorial, ignoring all interactions of order 3 and higher.

Alias pattern of the original $2^{7 - 3}$ design.

Figure 2: Alias pattern of the original \(2^{7 - 3}\) design.

Parsing this matrix, the effects derived from alias groups are \[\begin{align*} [A] = A + BD + CE + FG \\ [B] = B + AD + CF + EG \\ [C] = C + AE + BF + DG \\ [D] = D + AB + CG + EF \\ [E] = E + AC + BG + DF \\ [F] = F + BC + BG + DE \\ [G] = G + CD + BE + AF \end{align*}\]

Alias pattern after a full foldover. Note that the signs between main effects and their aliased interactions have switched.

Figure 3: Alias pattern after a full foldover. Note that the signs between main effects and their aliased interactions have switched.

  1. Now, suppose we reversed the signs of all the factors. What happens to the alias groups? The signs for the second order interactions flip! The resulting effect estimates are \[\begin{align*} [A]^{fold} = A - BD - CE - FG \\ [B]^{fold} = B - AD - CF - EG \\ [C]^{fold} = C - AE - BF - DG \\ [D]^{fold} = D - AB - CG - EF \\ [E]^{fold} = E - AC - BG - DF \\ [F]^{fold} = F - BC - BG - DE \\ [G]^{fold} = G - CD - BE - AF \end{align*}\]

The punchline is that we can now estimate the main effects without any aliasing, \[\begin{align*} A = \frac{1}{2}\left(\left[A\right] + \left[A\right]^{fold}\right) \\ B = \frac{1}{2}\left(\left[B\right] + \left[B\right]^{fold}\right) \\ C = \frac{1}{2}\left(\left[C\right] + \left[C\right]^{fold}\right) \\ D = \frac{1}{2}\left(\left[D\right] + \left[D\right]^{fold}\right) \\ E = \frac{1}{2}\left(\left[E\right] + \left[E\right]^{fold}\right) \\ F = \frac{1}{2}\left(\left[F\right] + \left[F\right]^{fold}\right) \\ G = \frac{1}{2}\left(\left[G\right] + \left[G\right]^{fold}\right) \\ \end{align*}\]

  1. This is in fact a general principle for dealising main effects from second order interactions. When you flip the signs of all factors in an original fractional factorial design, you will get a cancellation of second-order terms when you add pairs of effect estimates.

Data Example

  1. Let’s use these ideas to study effects in the eye data experiment. Let’s first make a Daniel plot of the effects we’d find when running the fractional factorial before foldover.
eye <- read_table2("https://uwmadison.box.com/shared/static/zh7majh2s6gesnu6f27fl17ncqfuwzev.txt") %>%
  mutate_at(vars(A:G), code)
eye1 <- eye[eye$Seq == 1, ]
fit <- lm(y ~ A * B * C * D * E * F, data = eye1)
effects <- coef(fit)[-1]
daniel_plot(effects, probs = c(0.1, 0.5))
From the original fraction, it seems that the effects for [A], [B], and [D] are important.

Figure 4: From the original fraction, it seems that the effects for [A], [B], and [D] are important.

It seems like \(\left[B\right], \left[D\right]\), and / or \(\left[A\right]\) are important. Inspecting the corresponding alias groups, and using the heredity principle, some plausible situations are * \(A, B, D\) are important * \(A, B, AB\) are important * \(A, D, AD\) are important * \(B, D, BD\) are important

  1. But without more information, we can’t draw further conclusions. To that end, suppose we’ve run the full foldover experiment. Let’s estimate effects in this run and then add them to effects from before – this is how we can estimate the main effects.
fit <- lm(y ~ A * B * C * D * E * F, data = eye[eye$Seq == 2, ])
effects_fold <- coef(fit)[-1]
0.5 * (effects + effects_fold)[1:6]
      A       B       C       D       E       F 
 0.7375 19.0250 -0.9000 14.6875  0.0625  0.2500 

It’s now clear that the main effect for \(A\) is in fact not important. The only plausible situation is that \(B, D\) and the \(BD\) interaction are strong.

Single-Factor Foldover

  1. Imagine that we want to dealias main and interaction effects associated with a single factor in the study,
  1. The mechanics at work here are similar to those in the full foldover. As before, let’s focus attention on the \(2^{7 - 3}_{III}\). Remember that the effect estimates were, \[\begin{align*} [A] = A + BD + CE + FG \\ [B] = B + AD + CF + EG \\ [C] = C + AE + BF + DG \\ [D] = D + AB + CG + EF \\ [E] = E + AC + BG + DF \\ [F] = F + BC + BG + DE \\ [G] = G + CD + BE + AF \end{align*}\]

  2. Suppose we flip the sign of factor \(D\) in the follow-up run. The new effect estimates would be, \[\begin{align*} [A]^{fold} &= A - BD + CE + FG \\ [B]^{fold} &= B - AD + CF + EG \\ [C]^{fold} &= C + AE + BF + DG \\ [D]^{fold} &= -D + AB + CG + EF \\ [E]^{fold} &= E + AC + BG - DF \\ [F]^{fold} &= F + BC + BG - DE \\ [G]^{fold} &= G - CD + BE + AF \end{align*}\]

  3. In particular, notice that we can estimate the main effect of \(D\) using \[\begin{align*} D = \frac{1}{2}\left(\left[D\right] - \left[D\right]^{fold}\right) \end{align*}\] and interactions involving \(D\) using, for example, \[\begin{align*} AD = \frac{1}{2}\left(\left[B\right] - \left[B\right]^{fold}\right). \end{align*}\]